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On 10/22/2024 10:18 AM, joes wrote:But HHH only does so INCOMPLETELY.Am Tue, 22 Oct 2024 08:47:39 -0500 schrieb olcott:void DDD()On 10/22/2024 4:50 AM, joes wrote:>Am Mon, 21 Oct 2024 22:04:49 -0500 schrieb olcott:On 10/21/2024 9:42 PM, Richard Damon wrote:On 10/21/24 7:08 PM, olcott wrote:On 10/21/2024 6:05 PM, Richard Damon wrote:On 10/21/24 6:48 PM, olcott wrote:On 10/21/2024 5:34 PM, Richard Damon wrote:On 10/21/24 12:29 PM, olcott wrote:On 10/21/2024 10:17 AM, joes wrote:Am Mon, 21 Oct 2024 08:41:11 -0500 schrieb olcott:On 10/21/2024 3:39 AM, joes wrote:>It's not like it will deterministically regenerate the same output.Did ChatGPT generate that?
If it did then I need *ALL the input that caused it to generate
that*>"naw, I wasn't lied to, they said they were saying the truth" sureI asked it if what it was told was a lie and it explained how whatNo, it said that given what you told it (which was a lie)No, someone using some REAL INTELEGENCE, as opposed to a programI specifically asked it to verify that its key assumption is
using "artificial intelegence" that had been loaded with false
premises and other lies.
correct and it did.
it was told is correct.
buddy.
>HAHAHAHAHA there isn't anything about truth in there, prove me wrongBecause Chat GPT doesn't care about lying.ChatGPT computes the truth and you can't actually show otherwise.Just no. Do you believe that I didn't write this myself after all?That seems to indicate that you are admitting that you cheated when youI definitely typed something out in the style of an LLM instead of myBecause what you are asking for is nonsense.I believe that the "output" Joes provided was fake on the basis that
Of course an AI that has been programmed with lies might repeat the
lies.
When it is told the actual definition, after being told your lies,
and asked if your conclusion could be right, it said No.
Thus, it seems by your logic, you have to admit defeat, as the AI,
after being told your lies, still was able to come up with the
correct answer, that DDD will halt, and that HHH is just incorrect to
say it doesn't.
she did not provide the input to derive that output and did not use
the required basis that was on the link.
own words /s
>Accepting your premises makes the problem uninteresting.If you want me to pay more attention to what you say, you first needYou cannot show that my premises are actually false.
to return the favor, and at least TRY to find an error in what I say,
and be based on more than just that you think that can't be right.
But you can't do that, as you don't actually know any facts about the
field that you can point to qualified references.
To show that they are false would at least require showing that they
contradict each other.
discussed this with ChatGPT. You gave it a faulty basis and then argued
against that.
>They also conventional within the context of software engineering. Thatlol
software engineering conventions seem incompatible with computer science
conventions may refute the latter.
>The a halt decider must report on the behavior that itself is containedJust because you don't like the undecidability of the halting problem?
within seems to be an incorrect convention.
>u32 HHH1(ptr P) // line 721That makes no sense. DDD halts or doesn't either way. HHH and HHH1 may
u32 HHH(ptr P) // line 801
The above two functions have identical C code except for their name.
>
The input to HHH1(DDD) halts. The input to HHH(DDD) does not halt. This
conclusively proves that the pathological relationship between DDD and
HHH makes a difference in the behavior of DDD.
give different answers, but then exactly one of them must be wrong.
Do they both call HHH? How does their execution differ?
>
{
HHH(DDD);
return;
}
*It is a verified fact that*
(a) Both HHH1 and HHH emulate DDD according to the
semantics of the x86 language.
(b) HHH and HHH1 have verbatim identical c sourceSo? the fact the give different results just proves that they must have a "hidden input" thta gives them that different behavior, so they can't be actually deciders.
code, except for their differing names.
(c) DDD emulated by HHH has different behavior thanNo, just less of it because HHH aborts its emulation.
DDD emulated by HHH1.
(d) Each DDD *correctly_emulated_by* any HHH thatNo, it can not be emulated by that HHH to that point, but that doesn't mean that the behavior of program DDD doesn't get there.
this DDD calls cannot possibly return no matter
what this HHH does.
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