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On 10/28/24 9:09 PM, olcott wrote:When HHH (unknowingly) emulates itself emulating DDD thisOn 10/28/2024 6:56 PM, Richard Damon wrote:Then how did it convert the call HHH into an emulation of DDD again?>>
It is IMPOSSIBLE to emulate DDD per the x86 semantics without the code for HHH, so it needs to be part of the input.
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*You seemed to be a totally Jackass here*
You are not that stupid
You are not that ignorant
and this is not your ADD
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_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
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At machine address 0000217a HHH emulates itself emulating
DDD without knowing that it is emulating itself.
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