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On 11/6/2024 8:39 AM, Mikko wrote:Not really. The original problem was not a halting problem but Turing'sOn 2024-11-05 13:18:43 +0000, olcott said:It has always been about whether or not a finite string input
On 11/5/2024 3:01 AM, Mikko wrote:Not in the original problem but the question whether a particular strictlyOn 2024-11-03 15:13:56 +0000, olcott said:void Infinite_Loop()
On 11/3/2024 7:04 AM, Mikko wrote:The halting probelm requires that every halt decider terminates.On 2024-11-02 12:24:29 +0000, olcott said:Yes it is the particular mapping required by the halting problem.
HHH does compute the mapping from its input DDDYes but not the particular mapping required by the halting problem.
to the actual behavior that DDD specifies and this
DOES INCLUDE HHH emulating itself emulating DDD.
The exact same process occurs in the Linz proof.
If HHH(DDD) terminates so does DDD. The halting problmen requires
that if DDD terminates then HHH(DDD) accepts as halting.
{
HERE: goto HERE;
return;
}
No that is false.
The measure is whether a C function can possibly
reach its "return" instruction final state.
C function will ever reach its return instruction is equally hard. About
specifies a computation that reaches its final state.
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