Liste des Groupes | Revenir à theory |
On 2024-11-07 16:39:57 +0000, olcott said:The halting problem has always been abuut halting
On 11/7/2024 3:56 AM, Mikko wrote:In early times there was variation in how things were presented and whatOn 2024-11-06 15:26:06 +0000, olcott said:>
>On 11/6/2024 8:39 AM, Mikko wrote:>On 2024-11-05 13:18:43 +0000, olcott said:>
>On 11/5/2024 3:01 AM, Mikko wrote:>On 2024-11-03 15:13:56 +0000, olcott said:>
>On 11/3/2024 7:04 AM, Mikko wrote:>On 2024-11-02 12:24:29 +0000, olcott said:>
>HHH does compute the mapping from its input DDD>
to the actual behavior that DDD specifies and this
DOES INCLUDE HHH emulating itself emulating DDD.
Yes but not the particular mapping required by the halting problem.
Yes it is the particular mapping required by the halting problem.
The exact same process occurs in the Linz proof.
The halting probelm requires that every halt decider terminates.
If HHH(DDD) terminates so does DDD. The halting problmen requires
that if DDD terminates then HHH(DDD) accepts as halting.
void Infinite_Loop()
{
HERE: goto HERE;
return;
}
>
No that is false.
The measure is whether a C function can possibly
reach its "return" instruction final state.
Not in the original problem but the question whether a particular strictly
C function will ever reach its return instruction is equally hard. About
It has always been about whether or not a finite string input
specifies a computation that reaches its final state.
Not really. The original problem was not a halting problem but Turing's
Exactly. The actual Halting Problem was called that by Davis
in 1952. Not the same as Turing proof.
words were used. Post had studied the halting problem of his tag system
much earlier but didn't call it a machine. Many other problems were also
studied and later found to be more or less related to the halting
problem and its variants.
*So we are back to The Halting Problem itself*No, it has been a collection of related problems that includes that
>
has always been about whether or not a finite string input
specifies a computation that reaches its final state.
particular one.
As the problems are related and equally hard it doesIt is not the meaning of words it is the semantic
not really matter which one you choose as long as you are clear
about your choice. To argue about the meaning of words id a clear
indcation of an intent to avoid an honest discussion.
Les messages affichés proviennent d'usenet.