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On 11/9/2024 3:53 AM, Mikko wrote:No, nothing you have said tells anuything about meanings of the bytesOn 2024-11-08 14:39:20 +0000, olcott said:It is the meaning of the bytes of x86 code and
On 11/8/2024 6:39 AM, Mikko wrote:Nevertheless Turing's solution to his circularity problem is usuallyOn 2024-11-07 16:39:57 +0000, olcott said:The halting problem has always been abuut halting
On 11/7/2024 3:56 AM, Mikko wrote:In early times there was variation in how things were presented and whatOn 2024-11-06 15:26:06 +0000, olcott said:Exactly. The actual Halting Problem was called that by Davis
On 11/6/2024 8:39 AM, Mikko wrote:Not really. The original problem was not a halting problem but Turing'sOn 2024-11-05 13:18:43 +0000, olcott said:It has always been about whether or not a finite string input
On 11/5/2024 3:01 AM, Mikko wrote:Not in the original problem but the question whether a particular strictlyOn 2024-11-03 15:13:56 +0000, olcott said:void Infinite_Loop()
On 11/3/2024 7:04 AM, Mikko wrote:The halting probelm requires that every halt decider terminates.On 2024-11-02 12:24:29 +0000, olcott said:Yes it is the particular mapping required by the halting problem.
HHH does compute the mapping from its input DDDYes but not the particular mapping required by the halting problem.
to the actual behavior that DDD specifies and this
DOES INCLUDE HHH emulating itself emulating DDD.
The exact same process occurs in the Linz proof.
If HHH(DDD) terminates so does DDD. The halting problmen requires
that if DDD terminates then HHH(DDD) accepts as halting.
{
HERE: goto HERE;
return;
}
No that is false.
The measure is whether a C function can possibly
reach its "return" instruction final state.
C function will ever reach its return instruction is equally hard. About
specifies a computation that reaches its final state.
in 1952. Not the same as Turing proof.
words were used. Post had studied the halting problem of his tag system
much earlier but didn't call it a machine. Many other problems were also
studied and later found to be more or less related to the halting
problem and its variants.
*So we are back to The Halting Problem itself*No, it has been a collection of related problems that includes that
has always been about whether or not a finite string input
specifies a computation that reaches its final state.
particular one.
regarded as the first solution to the halting problem.
As the problems are related and equally hard it does
not really matter which one you choose as long as you are clear
about your choice. To argue about the meaning of words id a clear
indcation of an intent to avoid an honest discussion.It is not the meaning of words it is the semanticAbove you have argued about the meanings of the words and
property of the finite string pair HHH/DDD.
keep doing so below.
bytes of code are not words.
It can and does if HHH is a decider and otherwise does not matter.The computation specified by the finite string DDDThe halting problem has always been about whether a finiteFrom https://www.tutorialspoint.com/automata_theory/ turing_machine_halting_problem.htm
string input specifies a computation that will reach its
final halt state.
If you disagree then you must provide a complete and coherent
counter-example conclusively proving otherwise not merely
some vague reference to some other things somewhere else.
Turing Machine Halting Problem
Input − A Turing machine and an input string w.
Problem − Does the Turing machine finish computing of the string w in a finite number of steps? The answer must be either yes or no.
emulated by HHH cannot possibly reach its "return"
instruction final halt state.
The computation specified by the finite string DDDHHH1 can take same inputs as HHH. These inputs specify some behaviour.
emulated by HHH1 IS NOT THE ACTUAL INPUT TO HHH.
HHH must compute the mapping FROM ITS INPUT TO THENot to full behaviour but to one feature of that behaviour.
BEHAVIOR THAT THIS INPUT SPECIFIES.
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