Sujet : Re: The philosophy of computation reformulates existing ideas on a new basis ---x86 code is a liar?
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theoryDate : 13. Nov 2024, 00:44:26
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <37890bcdc689d15e787a9e0853b4bc97cb6b2dfc@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
User-Agent : Mozilla Thunderbird
On 11/12/24 9:49 AM, olcott wrote:
On 11/12/2024 8:23 AM, joes wrote:
Am Tue, 12 Nov 2024 07:58:03 -0600 schrieb olcott:
On 11/12/2024 1:12 AM, joes wrote:
Am Mon, 11 Nov 2024 10:35:57 -0600 schrieb olcott:
On 11/11/2024 10:25 AM, joes wrote:
Am Mon, 11 Nov 2024 08:58:02 -0600 schrieb olcott:
On 11/11/2024 4:54 AM, Mikko wrote:
On 2024-11-09 14:36:07 +0000, olcott said:
On 11/9/2024 7:53 AM, Mikko wrote:
>
The actual computation itself does involve HHH emulating itself
emulating DDD. To simply pretend that this does not occur seems
dishonest.
Which is what you are doing: you pretend that DDD calls some other
HHH that doesn’t abort.
DDD emulated by HHH does not reach its "return" instruction
whether HHH aborts its emulation or not.
>
No. When the HHH that simulates DDD aborts, it also means that the HHH
that DDD calls aborts,
In no case does DDD emulated by any HHH that aborts at
some point or not
does the emulated DDD ever reach its "return" instruction
final halt state.
Disagreeing with verified facts makes you ignorant or
dishonest.
But the partial emulation of DDD by HHH is not a proper criteria, so yoiuy are just pointing out that you are just lying about what you are doing.
…