Re: The philosophy of computation reformulates existing ideas on a new basis

On 11/13/2024 2:37 AM, joes wrote:

Am Tue, 12 Nov 2024 16:45:10 -0600 schrieb olcott:

On 11/12/2024 5:22 AM, Mikko wrote:

On 2024-11-11 15:15:09 +0000, olcott said:

On 11/11/2024 5:06 AM, Mikko wrote:

On 2024-11-09 14:56:14 +0000, olcott said:

On 11/9/2024 3:53 AM, Mikko wrote:

 

THere is similar ambiguity in x86 semantics as there are operation
codes that are defined on some x86 processor models but undefined on
others, and it is also undefined what happens on a jump to a address in
a non-exstent or uninitialised memory.

Anyone with sufficient understanding of the x86 language fully well
knows that no DDD emulated by any HHH can possibly reach past its own
[0000217a] machine address.

Only if the called HHH doesn’t halt. Why doesn’t it?
 

You can keep dishonestly removing the code that I
am referring to.
_DDD()
[00002172] 55         push ebp      ; housekeeping
[00002173] 8bec       mov ebp,esp   ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404     add esp,+04
[00002182] 5d         pop ebp
[00002183] c3         ret
Size in bytes:(0018) [00002183]
DDD emulated by HHH keeps cycling through the first
four instructions from [00002172] to [0000217a] and
thus cannot possibly reach past its own machine address
[0000217a] whether HHH halts or not.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer