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On 11/13/2024 5:57 AM, Alan Mackenzie wrote:But your changing the meaning of the terms just shows that you are just a liar.olcott <polcott333@gmail.com> wrote:It is very easy if your weren't stuck in rebuttal modeOn 11/10/2024 2:36 PM, Alan Mackenzie wrote:>olcott <polcott333@gmail.com> wrote:On 11/10/2024 1:04 PM, Alan Mackenzie wrote:>[ .... ]>I have addressed your point perfectly well. Gödel's theorem is correct,
therefore you are wrong. What part of that don't you understand?>YOU FAIL TO SHOW THE DETAILS OF HOW THIS DOES
NOT GET RID OF INCOMPLETENESS.>The details are unimportant. Gödel's theorem is correct. Your ideas
contradict that theorem. Therefore your ideas are incorrect. Again, the
precise details are unimportant, and you wouldn't understand them
anyway. Your ideas are as coherent as 2 + 2 = 5.
>Incomplete(L) ≡ ∃x ∈ Language(L) ((L ⊬ x) ∧ (L ⊬ ¬x))>
When the above foundational definition ceases to exist then
Gödel's proof cannot prove incompleteness.*You just don't understand this at its foundational level*>
You make me laugh, sometimes (at you, not with you).
>
What on Earth do you mean by a definition "ceasing to exist"? Do you
mean you shut your eyes and pretend you can't see it?
>
not giving a rat's ass for truth you would already know.
A set as a member of itself ceases to exist in ZFC, thus
making Russell's Paradox cease to exist in ZFC.
Incompleteness exists as a concept, whether you like it or not. Gödel'sWhen the definition of Incompleteness:
theorem is proven, whether you like it or not (evidently the latter).
>
Incomplete(L) ≡ ∃x ∈ Language(L) ((L ⊬ x) ∧ (L ⊬ ¬x))
becomes
¬TruthBearer(L,x) ≡ ∃x ∈ Language(L) ((L ⊬ x) ∧ (L ⊬ ¬x))
Then meeting the criteria for incompleteness means something
else entirely and incompleteness can no longer be proven.
After 2000 years most of the greatest experts in the worldNope, that has well been know. You are just too stupid to see how the actual logic works.
still believe that "This sentence is not true" is undecidable
rather than incorrect.
But that sequence can be infinite, while the proof can not be.As for your attempts to pretend that unprovable statements are the sameI never said anything like that. You are so stuck on rebuttal
as false statements,
that you can't even keep track on the exact words that I
actually said.
I never said that ~True(L,x) == False(L,x). That is an egregious
error on your part. I have been saying the direct opposite of your
claim for years now. False(L, x) == True(L, ~x)
There cannot possibly be any expressions of language that
are true in L that are not determined to be true on the
basis of applying a sequence of truth preserving operations
in L to Haskell_Curry_Elementary_Theorems in L.
https://www.liarparadox.org/Haskell_Curry_45.pdfAnd might need an infinite sequence, and thus not provable.
Everything that is true on the basis of its meaning
expressed in language is shown to be true this exact
same way, within this same language.
Logicians take the prior work of other humans as inherentlyNo, idiots like you just ignore how logic works.
infallible. Philosophers of logic examine alternative views
that may be more coherent.
Mark Twain got it right when he asked "How many legs
does a dog have if you call a tail a leg?". To which the answer is
"Four: calling a tail a leg doesn't make it one.".
>-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius>
hits a target no one else can see." Arthur Schopenhauer
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