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On 11/16/2024 12:31 PM, joes wrote:But the behavior of DDD emulated by HHH isn't a valid semantic property, so you are just talking gibberish.Am Sat, 16 Nov 2024 11:18:33 -0600 schrieb olcott:*We are not talking any and damn H nitwit*On 11/16/2024 10:51 AM, joes wrote:>Am Sat, 16 Nov 2024 09:17:21 -0600 schrieb olcott:On 11/16/2024 8:26 AM, Richard Damon wrote:On 11/16/24 9:09 AM, olcott wrote:On 11/16/2024 6:36 AM, Richard Damon wrote:On 11/15/24 11:17 PM, olcott wrote:On 11/15/2024 10:10 PM, Richard Damon wrote:On 11/15/24 10:57 PM, olcott wrote:On 11/15/2024 9:39 PM, Richard Damon wrote:On 11/15/24 10:32 PM, olcott wrote:On 11/15/2024 9:18 PM, Richard Damon wrote:On 11/15/24 7:34 PM, olcott wrote:On 11/14/2024 8:49 PM, Richard Damon wrote:On 11/14/24 9:38 PM, olcott wrote:On 11/14/2024 2:33 PM, Richard Damon wrote:On 11/14/24 3:28 PM, olcott wrote:On 11/14/2024 2:22 PM, Alan Mackenzie wrote:joes <noreply@example.org> wrote:It absolutely does. If the inner HHH aborts, the outer doesn't need to,Which HHH does DDD call, the one that aborts?This has never made any damn difference.
because DDD halts.
>That I have to keep telling you this seems to indicate that you are aYou don't need to. I am talking about the inner H called by D, not the
liar.
outermost H simulating D.
>
We are talking about the behavior of DDD emulated
by any possible encoding of HHH at any level of
recursive emulation.
(a) HHH must report on the behavior of its input DDDAnd that behavior is DEFINED as the behavior of an unbounded emulation of that input, which must be the representation of a FULL program, NOT the partial emulaiton done by HHH.
it is ridiculously stupid to think otherwise.
int sum(int x, int y) { return x + y; }Right, and HHH is only allowed to report on the behavior of DDD run, or by equivalence, the behaviof of UTM(DDD).
is only allowed to return 5 for sum(3,2).
(b) The behavior of DDD emulated by any HHH no matterBut the emulation done by HHH of DDD is NOT the behavior of the input, and isn't even a valid semantic property of it.
how it is encoded or at whatever level of emulation no
matter how deep IS ALWAYS EXACTLY THE SAME IN THAT IT
CANNOT POSSIBLY REACH ITS OWN "return" FINAL HALT STATE.
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