Re: HHH(DDD) computes the mapping from its input to HHH emulating itself emulating DDD --- anyone that says otherwise is a liar

On 11/22/2024 9:16 AM, joes wrote:

Am Fri, 22 Nov 2024 08:50:33 -0600 schrieb olcott:

On 11/22/2024 6:20 AM, joes wrote:

Am Thu, 21 Nov 2024 15:19:43 -0600 schrieb olcott:

On 11/21/2024 3:11 PM, joes wrote:

Am Thu, 21 Nov 2024 09:19:03 -0600 schrieb olcott:

On 11/20/2024 10:00 PM, Richard Damon wrote:

On 11/20/24 9:57 PM, olcott wrote:

On 11/20/2024 5:51 PM, Richard Damon wrote:

On 11/20/24 5:03 PM, olcott wrote:

On 11/20/2024 3:53 AM, Mikko wrote:

On 2024-11-20 03:23:12 +0000, olcott said:

On 11/19/2024 4:12 AM, Mikko wrote:

On 2024-11-18 20:42:02 +0000, olcott said:

On 11/18/2024 3:41 AM, Mikko wrote:

The "the mapping" on the subject line is not correct. The
subject line does not specify which mapping and there is no
larger context that could specify that. Therefore it should
be "a mapping".
On 2024-11-17 18:36:17 +0000, olcott said:

>

My code is one example of the infinite set of every possible HHH
that emulates DDD according to the semantics of the x86 language.

Like all of them, it is unable to simulate DDD to its undeniable
halting state.

>

But it gets the wrong answer for the halting problem, as DDD dpes
halt.

DDD emulated by HHH does not halt.

Whatever. DDD halts and HHH should return that.

IT IS NOT THE SAME INSTANCE OF DDD.

All instances of DDD behave the same (if it is a pure function and the
HHH called from it doesn't switch behaviour by a static variable).

Only HHH is required to be a pure function, DDD is expressly allowed to
be any damn thing.

TMs don't have side effects, such as reading a static Root variable.
 

As I have said several times now (and everyone ignores
because they would rather disagree than be honest)
The static root variable has not one damn thing to do
with the verified fact that DDD emulated by HHH cannot
possibly reach its own "return" instruction final halt
state.

The behavior of DDD emulated by HHH is
different than the actual behavior of DDD emulated by HHH1.

Yes. HHH simulates it incorrectly.
 

That you are a clueless wonder about the x86 language
and still incorrectly denigrate my work on the basis
of your own ignorance <IS> The reckless disregard for
the truth that loses defamation cases.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer