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On 12/8/2024 4:55 AM, Mikko wrote:On 2024-12-05 04:20:50 +0000, olcott said:
There is an 80% chance that I will be alive in one month.This is not a useful main. It is sufficient to determine whether HHH
There may be an extended pause in my comments.
I will try to bring a computer to the out of town hospital.
On 12/4/2024 8:16 PM, Richard Damon wrote:On 12/4/24 8:50 PM, olcott wrote:It proves that HHH does emulate itself emulating DDD.On 12/4/2024 7:45 PM, Richard Damon wrote:Nope.On 12/4/24 8:41 PM, olcott wrote:Yes you fucking jackass this conclusively proves thatOn 12/4/2024 7:31 PM, Richard Damon wrote:What's the lie?On 12/4/24 8:06 PM, olcott wrote:Why do you have to keep fucking lying about this?On 12/4/2024 6:11 PM, Richard Damon wrote:Just a nonsense sentence, since HHH can't emulate HHH as it isn't given it,On 12/4/24 9:27 AM, olcott wrote:DDD emulated by any HHH according to the semantics ofOn 12/3/2024 5:39 PM, Richard Damon wrote:But the behaivor that HHH shows that it has *IS* an "answer",On 12/3/24 6:08 PM, olcott wrote:I did not mention anything about answers my entireOn 12/3/2024 3:03 AM, joes wrote:Am Mon, 02 Dec 2024 20:48:49 -0600 schrieb olcott:On 11/28/2024 1:48 PM, joes wrote:But only if your think that wrong answer can be right.Please try and explain how you are not dishonest what youYou said:We know that HHH halts. It doesn't simulate itself halting.
>>> HHH can't simulate itself.
That is WRONG !!!
HHH DOES EMULATE ITSELF PROVING THAT IT CAN EMULATE ITSELF.
try to change the subject from my rebuttal of your statement:
>>> HHH can't simulate itself.
That HHH does emulate itself emulating DDD proves
THAT IT CAN DO THIS.
scope is that HHH does emulate itself emulating DDD
thus conclusively proving that HHH can emulated itself
emulating DDD.
Whenever you go out-of-scope like this it surely
seems dishonest to me.
the x86 language cannot possibly reach its "ret" instruction
whether HHH aborts this emulation after N steps or never aborts.
I could die on the operating table in two weeks!
Can you point to what I say that is wrong, and a reliable reference that show it?
All you have is your own lies to call it a lie.
And yes, you might die in two weeks, and the only thing you will have left behind is all your lies.
HHH does emulate itself emulating DDD.
https://github.com/plolcott/x86utm/blob/master/Halt7.c
It proves that your HHH fails to meet its requirement to be pure function
Once we get through this point then we know that DDD
does not halt:
DDD emulated by any HHH according to the semantics of
the x86 language cannot possibly reach its "ret" instruction
whether HHH aborts this emulation after N steps or never aborts.
*This tells us that DDD emulated by HHH DOES NOT HALT*
We do not begin to examine whether or not HHH found this
answer as a pure function until after we agree with the
prior point.
*In all of the history of the halting problem there*
*have never been a correct return value for this*
typedef void (*ptr)();
int HHH(ptr P);
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
int main()
{
HHH(DD);
}
returns but not to determine whther it returns the correct value.
When we understand that the first point is correctThis is one of the well known methods to prove that the value HHH returns
then we know that HHH returning 0 is correct.
*This has much has never ever been done before*
is incorrect. If HHH returns 0 then DD returns 0 but the meaning of 0 in
this context is that DD does not halt. THerefore the value returned by
HHH is incorrect.
Every expert in the C programming language has agreed that DDNo, they not. They have agreed that DD returns only if HHH returns
simulated by HHH cannot possibly return.
Everyone disagreeing with this has dishonestly used to strawmanThe topic as specified on the subject line is the behaviour of DD and
deception to refer to different behavior than DD simulated by HHH.
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