Re: Anyone with sufficient knowledge of C knows that DD specifies non-terminating behavior to HHH

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Sujet : Re: Anyone with sufficient knowledge of C knows that DD specifies non-terminating behavior to HHH
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theory
Date : 10. Feb 2025, 13:41:29
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <f7e1f2c4a10774be2c22f1c68f9c7bbae2e4bfae@i2pn2.org>
References : 1 2 3 4 5 6 7
User-Agent : Mozilla Thunderbird
On 2/10/25 6:58 AM, olcott wrote:
On 2/10/2025 2:35 AM, Mikko wrote:
On 2025-02-09 15:24:53 +0000, olcott said:
>
On 2/9/2025 4:08 AM, Mikko wrote:
On 2025-02-08 14:55:09 +0000, olcott said:
>
On 2/8/2025 4:25 AM, Mikko wrote:
On 2025-02-07 23:13:04 +0000, olcott said:
>
Experts in the C programming language will know that DD
correctly simulated by HHH cannot possibly reach its own
"if" statement.
>
Wrong, they understand that nothing below exludes the possibility that
HHH is a program that can correctly simulate DD to its "if" statement.
>
Show the execution trace of that.
>
Your request does not make sense. Non-existence of a exclusion does not
have an execution trace.
>
The code of HHH might exlude that but that is not sohwn below.
>
The finite string DD specifies non-terminating recursive
simulation to simulating termination analyzer HHH.
>
No, it does not. DD as quoted below pecifies nothing about the behaviour
of HHH, only its argument types and return type.
>
>
 >>    int Halt_Status = HHH(DD); // line 3 of DD
Requires HHH to simulate itself simulating DD recursively.
>
No, it does not. I only requires that the execution of HHH with a function
pointer to DD must be started. OP does not show what happens next.
>
Within the context that HHH <is> a simulating termination
analyzer line 3 of DD proves that DD cannot possibly reach
its own "if" statement.
>
That is not the context of OP.
>
 That you did not bother to look at my paper does not entail
that the correct full context has not been provided. The
context has always been this paper for several years.
 https://www.researchgate.net/ publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D
 typedef void (*ptr)();
int HHH(ptr P);
 int DD()
{
   int Halt_Status = HHH(DD);
   if (Halt_Status)
     HERE: goto HERE;
   return Halt_Status;
}
 int main()
{
   HHH(DD);
}
 
And that paper just proves that you don't understand what you are talking about.
Your START with an error in your first paragraph, as the function DD is NOT a "Program" suitable to be analyzied for halting until you include the function HHH (and everything it calls) as the input.
Once you do that, the rest of the paper is invalid, as it is based on the concept that HHH is a variable that you can look at all values of.
Sorry, you are just proving yourself to be an ignorant FRAUD that uses lies and deceit to make your claims.

Date Sujet#  Auteur
12 Jul 25 o 

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