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On 2/25/2025 5:41 PM, Richard Damon wrote:No, it is dead obvious that since the HHH that DD DOES ABORT (and to say otherwise is just a DAMNED LIE) then the behavior of the executed DD is to return.On 2/25/25 4:16 PM, olcott wrote:Only if you are clueless about both c and x86, otherwiseOn 2/25/2025 8:35 AM, Mikko wrote:>On 2025-02-24 23:22:23 +0000, olcott said:>
>On 2/24/2025 2:32 AM, Mikko wrote:>On 2025-02-23 17:34:21 +0000, olcott said:>
>On 2/23/2025 3:43 AM, Mikko wrote:>On 2025-02-22 16:06:08 +0000, olcott said:>
>On 2/22/2025 2:45 AM, Mikko wrote:>On 2025-02-21 22:39:01 +0000, olcott said:>
>On 2/21/2025 2:10 AM, Mikko wrote:>On 2025-02-20 13:02:28 +0000, olcott said:>
>On 2/20/2025 2:28 AM, Mikko wrote:>On 2025-02-20 04:08:05 +0000, olcott said:>
>On 2/16/2025 6:55 AM, joes wrote:>Am Sat, 15 Feb 2025 21:25:12 -0600 schrieb olcott:>On 2/15/2025 4:03 AM, joes wrote:How interesting. Might this be due to a global variable that basicallyAm Fri, 14 Feb 2025 17:29:45 -0600 schrieb olcott:The first instance of recursion is not exactly the same as subsequentOn 2/14/2025 6:54 AM, joes wrote:Yes, please shut up.Am Thu, 13 Feb 2025 22:21:59 -0600 schrieb olcott:I will begin ignoring insincere replies.On 2/13/2025 9:15 PM, Richard Damon wrote:Why are you passing the wrong input to HHH?On 2/13/25 7:07 PM, olcott wrote:THAT IS A DIFFERENT INSTANCEOn 2/13/2025 3:20 AM, Mikko wrote:We havm, but you are too stupid to understand it.On 2025-02-13 04:21:34 +0000, olcott said:When you try to show the steps attempting to show that it is falseOn 2/12/2025 4:04 AM, Mikko wrote:The fact that the claim on subject line is false is not a truism.On 2025-02-11 14:41:38 +0000, olcott said:It is a truism and not one person on the face of the Earth can
>Doesn't matter when you don't say that you are talking aboutOf course not. However, the fact that no reference to thatThat paper and its code are the only thing that I have been
article before or when HHH
talking about in this forum for several years.
that paper.
Anyway, that is irrelevant to the fact that the subject line
contains a false claim.
possibly show otherwise.
In order to determine the claim is false one needs some knowledge
that is not obvious.
I will point out the error.
Since when DD run, it halts,
But why are you not passing the same instance to HHH?
instances of the exact same sequence of recursive invocations.
It is the same with recursive simulations. When the second recursive
invocation has been aborted the first one terminates normally misleading
people into believing that the recursive chain terminates normally.
toggles termination?
Termination analyzers determine whether or not their input
could possibly terminate normally. Nothing can toggle this.
Wrong. Termination analyzers deremine whether a program can run forever.
This would define simulating termination analyzers as impossible
because every input that would otherwise run forever is aborted.
It would be aborted by external causes but not by the program itself so
we can say that the program could run forever.
>
OK great we finally got mutual agreement on one point.
Unless the C function HHH aborts its simulation of the C
function DD this DD C function DOES NOT TERMINATE.
If you mean the HHH on https://github.com/plolcott/x86utm/ blob/ master/ Halt7.c
that statement is void: that HHH does abort is simulation of DD. If you mean
any function HHH allowed by OP then that statement is false.
>
I am not talking about one statement.
I am, about one you made: "Unless the C function HHH aborts its
simulation of the C function DD this DD C function DOES NOT TERMINATE."
>
If you mean the HHH on https://github.com/plolcott/x86utm/blob/ master/ Halt7.c
that statement is void: that HHH does abort is simulation of DD. If you mean
any function HHH allowed by OP then that statement is false.
Do you understand the notion of hypothetical possibilities?
It really seems that you do not.
Yes, I understand that a simulator that both abort its simulation and
does not abort is not a hypothetical possibility.
HHH aborts its emulation of DD.
When we imagine the exact same HHH with the
one single change that it never aborts its input
then we can see that this HHH cannot possibly
terminate normally.
That's right. But OP did not specify which HHH is called by DD.
>
DD does not terminate normally either way so it
is stupid to need to know which one.
>
OF course DD terminates normally if HHH aborts its simulation.
>
it is dead obvious that the entire recursive chain totally
stops and zero elements of the recursive chain can possibly
reach their "ret" or "return" instruction as soon as the
outermost instance is aborted.
Since this is ordinary software engineering and requires zeroNo, ait proves that you are just a clueless pathological liar.
knowledge of computer science that proves that anyone disagreeing
is simply clueless.
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