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On 2/28/2025 2:36 AM, Fred. Zwarts wrote:Op 27.feb.2025 om 22:42 schreef olcott:
Yes, HHH emulates DD verifiably incorrect.It is flat out incorrect to suggest that this DD is a different one.It is a verified fact that the directly executed DD has a different
There is only one finite string, describing only one behaviour.
execution trace than DD emulated by HHH.
People try to get away with saying this is wrong are dumbfounded when IIt is the trace of HHH1 emulating DD (where DD calls HHH).
challenge them to provide the correct execution trace of DD emulated by
HHH.
When we hypothesize that the code at machine address 0000213c is an x86HHH is not an emulator though.
emulator then we know that DD remains stuck in recursive emulation and
cannot possibly reach its own "ret" instruction and terminate normally.
When we add the additional complexity that HHH also aborts this sequenceYes it does, because HHH returns to DD.
at some point then every level of recursive emulation stops. This does
not enable any DD to ever reach its "ret" instruction.
If this is beyond your technical competence THAT DOES NOT MAKE ME WRONGThat this is beyond your technical competence does not make you right.
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