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On 2/28/2025 2:36 AM, Fred. Zwarts wrote:Then VERIFY IT,Op 27.feb.2025 om 22:42 schreef olcott:It is a verified fact that the directly executed DD has a>>
It is flat out dishonest to change the subject away
from DD emulated by HHH.
>
It is flat out incorrect to suggest that this DD is a different one. There is only one finite string, describing only one behaviour.
different execution trace than DD emulated by HHH.
People try to get away with saying this is wrong are dumbfoundedExecpt you don't, because you edit out parts you don't loke, and add in things that don't happen,
when I challenge them to provide the correct execution trace
of DD emulated by HHH.
_DD()So, why don't you do that?
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
It is perfectly fine to say that you just don't understand
that. What is terribly wrong is for you to know that you
don't understand that and claim that I am incorrect.
When we hypothesize that the code at machine addressAnd thus you prove that you arguement is built on the belief in a Truth Fairy that can make a statement true that isn't. At 0000213c isn't a correct emulator, but just a partial one that will abort its emulation and return. We know that as your arguement has it do that. Thus, your argument is based on LIES.
0000213c is an x86 emulator then we know that DD
remains stuck in recursive emulation and cannot possibly
reach its own "ret" instruction and terminate normally.
When we add the additional complexity that HHH alsoWhich makes it NOT a correct emulation, and breaks the conclusion you made about DD.
aborts this sequence at some point then every level
of recursive emulation stops. This does not enable
any DD to ever reach its "ret" instruction.
If this is beyond your technical competenceThat you dont understand how programs works, does.
THAT DOES NOT MAKE ME WRONG
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