Re: DD emulated by HHH cannot possibly terminate normally --- x86 code

Op 01.mrt.2025 om 22:11 schreef olcott:

On 3/1/2025 2:16 PM, Fred. Zwarts wrote:

Op 01.mrt.2025 om 17:33 schreef olcott:

On 3/1/2025 9:39 AM, Fred. Zwarts wrote:

Op 01.mrt.2025 om 15:41 schreef olcott:

On 3/1/2025 6:49 AM, Richard Damon wrote:

On 2/28/25 7:47 PM, olcott wrote:

_DD()
[00002133] 55         push ebp      ; housekeeping
[00002134] 8bec       mov ebp,esp   ; housekeeping
[00002136] 51         push ecx      ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404     add esp,+04
[00002144] 8945fc     mov [ebp-04],eax
[00002147] 837dfc00   cmp dword [ebp-04],+00
[0000214b] 7402       jz 0000214f
[0000214d] ebfe       jmp 0000214d
[0000214f] 8b45fc     mov eax,[ebp-04]
[00002152] 8be5       mov esp,ebp
[00002154] 5d         pop ebp
[00002155] c3         ret
Size in bytes:(0035) [00002155]
>
When we hypothesize that the code at machine address
0000213c is an x86 emulator then we know that DD
remains stuck in recursive emulation and cannot possibly
reach its own "ret" instruction and terminate normally.
>
When we add the additional complexity that HHH also
aborts this sequence at some point then every level
of recursive emulation immediately stops. This does
not enable any DD to ever reach its "ret" instruction.
>

>
But then you just negated your first assumption, as a partial emulator that aborts its emulation, then DD no longer gets stuck.
>

>
Cannot possibly reach its own "ret" instruction and terminate normally

proves failure of HHH to reach the end of a proven terminating program.

>
DD emulated by HHH according to the above x86 machine code of DD
cannot possibly reach its own "ret" instruction and terminate normally

>
>
In other words,

>
The DD input to HHH unequivocally specifies a
non terminating computation.

In other words, HHH did not terminate the simulation.