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On 2025-03-01 23:47:30 +0000, olcott said:I challenged everyone here to provide the machine address
On 3/1/2025 2:22 AM, Mikko wrote:On 2025-03-01 00:47:58 +0000, olcott said:>
>_DD()>
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
>
When we hypothesize that the code at machine address
0000213c is an x86 emulator then we know that DD
remains stuck in recursive emulation and cannot possibly
reach its own "ret" instruction and terminate normally.
The emulator itself is stuck and cannot return normally but it doesn't
know it cannot return normally. At some point it runs out of memory
and terminates normally or abnormally.
>
Yes you are correct about this sub-step of two steps.
>When we add the additional complexity that HHH also>
aborts this sequence at some point then every level
of recursive emulation immediately stops. This does
not enable any DD to ever reach its "ret" instruction.When we are answering the question that seems impossible forAlready answered.
anyone here to pay attention to even when repeated hundreds of times:
>
Can the above DD correctly emulated by HHH possibly
reach its own "ret" instruction and terminate normally?
The answer is dead obviously "no" for everyone that is:Only someone technically incompetent or deliberately deceptive believes that.
(a) Technically competent
and
(b) Not deliberately deceptive.
If DD correctly emulated by HHH
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