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On 3/10/2025 4:14 AM, Fred. Zwarts wrote:Why repeating what we agree with?Op 09.mrt.2025 om 14:11 schreef olcott:You have despicably changed my words.On 3/9/2025 4:05 AM, Fred. Zwarts wrote:>Op 08.mrt.2025 om 18:47 schreef olcott:>On 3/8/2025 9:41 AM, Fred. Zwarts wrote:Op 08.mrt.2025 om 15:09 schreef olcott:On 3/8/2025 3:06 AM, Mikko wrote:On 2025-03-07 15:11:53 +0000, olcott said:
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_DD()
[00002133] 55 push ebp ; housekeeping
[00002134] 8bec mov ebp,esp ; housekeeping
[00002136] 51 push ecx ; make space for local
[00002137] 6833210000 push 00002133 ; push DD
[0000213c] e882f4ffff call 000015c3 ; call HHH(DD)
[00002141] 83c404 add esp,+04
[00002144] 8945fc mov [ebp-04],eax
[00002147] 837dfc00 cmp dword [ebp-04],+00
[0000214b] 7402 jz 0000214f
[0000214d] ebfe jmp 0000214d
[0000214f] 8b45fc mov eax,[ebp-04]
[00002152] 8be5 mov esp,ebp
[00002154] 5d pop ebp
[00002155] c3 ret
Size in bytes:(0035) [00002155]
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DD correctly emulated by HHH cannot possibly reach
its own "ret" instruction and terminate normally
because DD calls HHH(DD) in recursive emulation.
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Why repeating things we agree with? We agree that HHH correctly reports that it cannot possibly complete the simulation to its end.
It never has been any failure of HHH.
It has always been that DD calls HHH(DD) in recursive
emulation thus specifying that it cannot possible reach
its own final state and terminate normally.
typedef void (*ptr)();
int HHH(ptr P);
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
int main()
{
HHH(DD);
}
DD correctly emulated by HHH cannot possibly reach
its own "return" instruction and terminate normally
because DD calls HHH(DD) in recursive emulation.
If HHH can see the same pattern that every competent
programmer sees then HHH does not need to emulate DD
more than twice to know that HHH cannot possibly reach
its own final state and terminate normally.
Perhaps you are not a competent programmer.
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