Re: Every sufficiently competent C programmer knows --- Truthmaker Maximalism

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Sujet : Re: Every sufficiently competent C programmer knows --- Truthmaker Maximalism
De : wyniijj5 (at) *nospam* gmail.com (wij)
Groupes : comp.theory
Date : 14. Mar 2025, 17:58:50
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <86fbc35155fbcb3e88cf0dd069d16d61e16bcf4e.camel@gmail.com>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
User-Agent : Evolution 3.54.3 (3.54.3-1.fc41)
On Fri, 2025-03-14 at 11:33 -0500, olcott wrote:
On 3/14/2025 11:01 AM, wij wrote:
On Fri, 2025-03-14 at 10:51 -0500, olcott wrote:
On 3/14/2025 10:04 AM, wij wrote:
On Fri, 2025-03-14 at 09:35 -0500, olcott wrote:>>
void DDD()
{
     HHH(DDD);
     return;
}
 
DDD correctly simulated by HHH cannot possibly reach
its own "return" instruction in any finite number of
correctly simulated steps.
 
That you are clueless about the semantics of something
as simple as a tiny C function proves that you are not
competent to review my work.
 
 
https://en.wikipedia.org/wiki/Halting_problem
In computability theory, the halting problem is the problem of determining, from a description
of
an
arbitrary computer program and an input, whether the program will finish running, or continue
to
run
forever.
 
That means: H(D)=1 if D() halts and H(D)=0 if D() does not halt..
 
But, it seems you don't understand English, as least as my level, .....
 
 
 
 
void DDD()
{
    HHH(DDD);
    return;
}
 
The only difference between HHH and HHH1 is that they are
at different locations in memory. DDD simulated by HHH1
has identical behavior to DDD() directly executed in main().
 
The semantics of the finite string input DDD to HHH specifies
that it will continue to call HHH(DDD) in recursive simulation.
 
The semantics of the finite string input DDD to HHH1 specifies
to simulate to DDD exactly once.
 
When HHH(DDD) reports on the behavior that its input finite
string specifies it can only correctly report non-halting.
 
When HHH(DDD) is required to report on behavior other than
the behavior that its finite string specifies HHH is not
a decider thus not a halt decider.
 
All deciders are required to compute the mapping from
their input finite string to the semantic or syntactic property
that this string specifies. Deciders return true when this
string specifies this property otherwise they return false.
 
 
Are you solving The Halting Problem or not? Yes or No.
 
 
 
I have only correctly refuted the conventional halting
problem proof. Actually solving the halting problem
requires a program that is ALL KNOWING thus God like.

I (GUR) had told you God cannot solve HP neither (maybe because the problem is limited in a box)

My actual specialty for the last 21 years is overcoming
how pathological self-reference has thwarted the correct
evaluation of expressions of language.

TM reads symbols, or just 1 and 0, there is no 'semantics' 
(pathological self-reference) there.

Of this very narrow and specific focus it seems that I
have more knowledge than anyone else in the world.

POO Halt seems based on the liar's paradox. But the HP proof is
not really isomorphic to liar's paradox. If HP proof is explained
in that way for convenience reasons.

The closest related field to my work is the philosophy
of Truth-maker maximalism
http://plato.stanford.edu/entries/truthmakers/#Max
gonzalo rodriguez-pereyra seems to be the leading
author in this field.
 

You are solving philosophical problem, not HP.

I have only worked on the subset of truth where the
truth of expressions of language only depends on a
connection to their semantic meaning expressed in
this same language (Olcott analytic truth).

You don't even understand the logical IF. what can I say?



Date Sujet#  Auteur
11 Mar 25 * Every sufficiently competent C programmer knows343olcott
11 Mar 25 +* Re: Every sufficiently competent C programmer knows25Richard Damon
11 Mar 25 i`* Re: Every sufficiently competent C programmer knows24olcott
11 Mar 25 i +- Re: Every sufficiently competent C programmer knows1dbush
11 Mar 25 i +* Re: Every sufficiently competent C programmer knows21Mikko
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11 Mar 25 i i +- Re: Every sufficiently competent C programmer knows1Richard Heathfield
11 Mar 25 i i +* Re: Every sufficiently competent C programmer knows4Mikko
11 Mar 25 i i i`* Re: Every sufficiently competent C programmer knows3olcott
11 Mar 25 i i i +- Re: Every sufficiently competent C programmer knows1Richard Damon
12 Mar 25 i i i `- Re: Every sufficiently competent C programmer knows1Mikko
11 Mar 25 i i +- Re: Every sufficiently competent C programmer knows1Richard Damon
16 Mar 25 i i `* Re: Every sufficiently competent C programmer knows13Mikko
16 Mar 25 i i  +* Re: Every sufficiently competent C programmer knows11Richard Heathfield
16 Mar 25 i i  i+* Re: Every sufficiently competent C programmer knows2Mikko
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16 Mar 25 i i  i +* Every sufficiently competent C programmer knows --- original post appended at end6olcott
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17 Mar 25 i i  i i`- Re: Every sufficiently competent C programmer knows --- original post appended at end1Mikko
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11 Mar 25 +- Re: Every sufficiently competent C programmer knows1Richard Heathfield
11 Mar 25 +* Re: Every sufficiently competent C programmer knows16Fred. Zwarts
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12 Mar 25   i iii`* Re: Every sufficiently competent C programmer knows2Mike Terry
12 Mar 25   i iii `- Re: Every sufficiently competent C programmer knows1Richard Heathfield
12 Mar 25   i ii+* Re: Every sufficiently competent C programmer knows44Fred. Zwarts
12 Mar 25   i iii`* Re: Every sufficiently competent C programmer knows43Mike Terry
12 Mar 25   i iii `* Re: Every sufficiently competent C programmer knows --- posthumous reviewers42olcott
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14 Mar 25   i iii  i i +- Re: Every sufficiently competent C programmer knows --- posthumous reviewers1Fred. Zwarts
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16 Mar 25   i iii  i i i   i`* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement4olcott
16 Mar 25   i iii  i i i   i `* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement3Richard Damon
17 Mar 25   i iii  i i i   i  `* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement2olcott
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16 Mar 25   i iii  i i i    `* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement5olcott
16 Mar 25   i iii  i i i     `* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement4dbush
16 Mar 25   i iii  i i i      `* Re: Every sufficiently competent C programmer knows --- Paraphrase of Sipser's agreement3olcott
15 Mar 25   i iii  i i `* Re: Every sufficiently competent C programmer knows --- posthumous reviewers4Mikko
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13 Mar 25   i iii  `- Re: Every sufficiently competent C programmer knows --- posthumous reviewers1Fred. Zwarts
13 Mar 25   i ii`* Re: Every sufficiently competent C programmer knows23Ben Bacarisse
12 Mar 25   i i`* Re: Every sufficiently competent C programmer knows3Mikko
11 Mar 25   i +* Re: Every sufficiently competent C programmer knows --- Stupid Mistake?2olcott
11 Mar 25   i +* Re: Every sufficiently competent C programmer knows --- Counter-Factual ERROR4olcott
12 Mar 25   i +* Re: Every sufficiently competent C programmer knows --- Very Stupid Mistake101olcott
12 Mar 25   i `* Re: Every sufficiently competent C programmer knows --- Mike's very stupid mistake93olcott
11 Mar 25   +* Re: Every sufficiently competent C programmer knows3Mikko
11 Mar 25   `* Re: Every sufficiently competent C programmer knows5Fred. Zwarts

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