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On 3/16/2025 12:42 PM, olcott wrote:He has not yet agreed.On 3/16/2025 10:32 AM, dbush wrote:And Sipser didn't agree to the paraphrase so it's just you giving your opinion.On 3/16/2025 11:05 AM, olcott wrote:I have new words you freaking moron Ben never saw these new words.On 3/16/2025 7:31 AM, joes wrote:>Am Sat, 15 Mar 2025 16:27:00 -0500 schrieb olcott:>On 3/15/2025 5:12 AM, Mikko wrote:On 2025-03-14 14:39:30 +0000, olcott said:YES.On 3/14/2025 4:03 AM, Mikko wrote:>On 2025-03-13 20:56:22 +0000, olcott said:>On 3/13/2025 4:22 AM, Mikko wrote:>On 2025-03-13 00:36:04 +0000, olcott said:>
>
>void DDD()>
{
HHH(DDD);
return;
}
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
>
When HHH correctly emulates N steps of the above functions none of
them can possibly reach their own "return" instruction and
terminate normally.
Nevertheless, assuming HHH is a decider, Infinite_Loop and
Infinite_Recursion specify a non-terminating behaviour, DDD
specifies a terminating behaviour
What is the sequence of machine language instructions of DDD
emulated by HHH such that DDD reaches its machine address 00002183?
Irrelevant off-topic distraction.
Proving that you don't have a clue that Rice's Theorem is anchored in
the behavior that its finite string input specifies.
Another irrelevant off-topic distraction, this time involving a false
claim.
One can be a competent C programmer without knowing anyting about
Rice's Theorem.
>Rice's Theorem is about semantic properties in general, not justDoes THE INPUT TO simulating termination analyzer HHH encode a C
behaviours.
The unsolvability of the halting problem is just a special case.
>
function that reaches its "return"
instruction [WHEN SIMULATED BY HHH] (The definition of simulating
termination analyzer) ???That can't be right. Otherwise my simulator could just not simulate>
at all and say that no input halts.
>
Originally a "decider" was any TM that always stops
running for any reason.
>
In computability theory, a decider is a Turing
machine that halts for every input.[1]
https://en.wikipedia.org/wiki/Decider_(Turing_machine)
>><MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>key word "correctly"
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
*I anchored what correct emulation means now*
>
<Accurate Paraphrase>
If emulating termination analyzer H emulates its input
finite string D of x86 machine language instructions
according to the semantics of the x86 programming language
until H correctly determines that this emulated D cannot
possibly reach its own "ret" instruction in any finite
number of correctly emulated steps then
>
H can abort its emulation of input D and correctly report
that D specifies a non-halting sequence of configurations.
</Accurate Paraphrase>
>
>
>
Nope:
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