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On 3/26/2025 2:44 AM, Mikko wrote:No it doesn't. Where do you get that from, since the DEFINITION of the behavior is that of the direct execution of the program it represents.On 2025-03-25 19:24:07 +0000, olcott said:When an input to a simulating termination analyzer
>Cannot possibly derive any outputs not computed from>
their inputs.
>
A Turing machine halt decider cannot possibly report
on the behavior of any directly executing process.
It can if that report is a computable function of their inputs.
For example, whether the direct execution of another Turing machine
is longer than 2 steps is Turing computable.
>
defines a pathological relationship to its simulating
termination analyzer this changes the behavior of this
input relative to its direct execution.
Simulating termination analyzers only report on theWHich *IS* the behavior of the direct execution of the program the input specified.
behavior that their input specifies.
When an input to a simulating termination analyzerNo, it doesn't
defines a pathological relationship to its simulating
termination analyzer this changes the behavior of this
input relative to its direct execution.
Simulating termination analyzers only report on theWhich is DEFINED to be the behavior of the program the input represents.
behavior that their input specifies.
HOW MANY TIMES DO I HAVE TO REPEAT THIS BEFOREYour problem is that you statements are just lies, which people ignore and point you to the correct meaning of the words.
YOU NOTICE THAT I SAID IT AT LEAST ONCE?
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