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On 3/30/2025 8:50 AM, Fred. Zwarts wrote:No, if the verifiers lies, then his "verification" isn't valid.Op 30.mrt.2025 om 04:35 schreef olcott:No it does not. That is a stupid thing to say.On 3/29/2025 8:12 PM, Richard Damon wrote:That completely depends on who has verified it.On 3/29/25 6:44 PM, olcott wrote:>On 3/29/2025 5:08 PM, dbush wrote:>On 3/29/2025 5:46 PM, olcott wrote:>On 3/29/2025 3:14 PM, dbush wrote:>On 3/29/2025 4:01 PM, olcott wrote:>On 3/29/2025 2:26 PM, dbush wrote:>On 3/29/2025 3:22 PM, olcott wrote:>On 3/29/2025 2:06 PM, dbush wrote:>On 3/29/2025 3:03 PM, olcott wrote:>On 3/29/2025 10:23 AM, dbush wrote:>On 3/29/2025 11:12 AM, olcott wrote:>On 3/28/2025 11:00 PM, dbush wrote:>On 3/28/2025 11:45 PM, olcott wrote:>>>
It defines that it must compute the mapping from
the direct execution of a Turing Machine
Which does not require tracing an actual running TM, only mapping properties of the TM described.
The key fact that you continue to dishonestly ignore
is the concrete counter-example that I provided that
conclusively proves that the finite string of machine
code input is not always a valid proxy for the behavior
of the underlying virtual machine.
In other words, you deny the concept of a UTM, which can take a description of any Turing machine and exactly reproduce the behavior of the direct execution.
I deny that a pathological relationship between a UTM and
its input can be correctly ignored.
>
In such a case, the UTM will not halt, and neither will the input when executed directly.
It is not impossible to adapt a UTM such that it
correctly simulates a finite number of steps of an
input.
>
1) then you no longer have a UTM, so statements about a UTM don't apply
We can know that when this adapted UTM simulates a
finite number of steps of its input that this finite
number of steps were simulated correctly.
And therefore does not do a correct UTM simulation that matches the behavior of the direct execution as it is incomplete.
>
It is dishonest to expect non-terminating inputs to complete.
An input that halts when executed directly is not non-terminating
>>>>>>2) changing the input is not allowed>
The input is unchanged. There never was any
indication that the input was in any way changed.
>
False, if the starting function calls UTM and UTM changes, you're changing the input.
>
When UTM1 is a UTM that has been adapted to only simulate
a finite number of steps
And is therefore no longer a UTM that does a correct and complete simulation
>and input D calls UTM1 then the>
behavior of D simulated by UTM1
>
Is not what I asked about. I asked about the behavior of D when executed directly.
>
Off topic for this thread.
UTM1 D DOES NOT HALT
UTM2 D HALTS
D is the same finite string in both cases.
>
No it isn't, not if it is the definition of a PROGRAM.
>
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
>
The behavior that these machine code bytes specify:
558bec6872210000e853f4ffff83c4045dc3
as an input to HHH is different than these
same bytes as input to HHH1 as a verified fact.
>Or, are you admitting you don't understand the meaning of a program?>
>
It seems that you "just don't believe in" verified facts.
>
Every verified fact IS TRUE BY DEFINITION.
Nope, it is proved incorrect by the ACTUAL meaning of the words you use, but then you LIE to yourself about what those words mean.If everyone can see that the way in which Olcott verifies his 'facts' is only a baseless claim, I do not believe in the verification. In particular when he does not fix the errors in the verification that were pointed out to him.My claims are verified as true entirely on the basis
of the meaning of their words.
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