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On 4/25/2025 8:56 AM, joes wrote:Am Thu, 24 Apr 2025 19:03:34 -0500 schrieb olcott:
Then it can't be due to that. It even works with HHH(HHH)!Mathematical induction proves that DD emulated by HHH cannot possibly
reach its own final state in an infinite number of steps and it does
this with one recursive emulation.
There is a repeating pattern that every C programmer can see.Like Fred wrote months ago, that has nothing to do with theSure it does. The contradictory part of DD has always been unreachable
contradictory part of DD,
thus only a ruse.
only with it being simulated by the same simulator it calls.That <is> the Halting Problem counter-example input.
No, the rules applied to DD (which is the input to HHH) derive "halting",The program EE(){ HHH(EE); } also halts and cannot be simulated by HHH.HHH cannot possibly do this without violating the rules of the x86
language.
The finite string transformation rules of the x86 language applied to
the input to HHH(DD) only correctly derive not halting.
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