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On 4/28/2025 3:21 PM, Richard Heathfield wrote:No, only if the input includes the same simulator. BlooP programsOn 28/04/2025 21:03, olcott wrote:Computing the actual behavior the direct execution of any input isOn 4/28/2025 2:58 PM, dbush wrote:Category error. The halting function below is fully defined, andNeither is the square root of an actual onion computable.
this mapping is not computable *as you have explicitly admitted*.
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Turing Computable Functions are required to apply finite string
transformations to their inputs. The function defined below ignores
that requirement PROVING THAT IT IS INCORRECT.
No, it proves that you agree that it's not a computable function. QED.
ALWAYS IMPOSSIBLE.
No halt decider can ever directly see the actual behavior of any--
directly executed input.
Given any algorithm (i.e. a fixed immutable sequence of instructions)
X described as <X> with input Y:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
directly
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