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On 4/29/2025 2:39 PM, Richard Heathfield wrote:No, the input specifies a halting program, but H cannot see that, because it was programmed to abort before it could analyse Halt7.c where it would see a conditional abort, which makes the program halt.On 29/04/2025 20:06, olcott wrote:THE CODE THAT IT CAN SEEOn 4/29/2025 8:46 AM, Richard Heathfield wrote:>On 29/04/2025 14:11, olcott wrote:>On 4/29/2025 2:10 AM, Richard Heathfield wrote:>On 29/04/2025 03:50, olcott wrote:
<snip>
>>>Yet it is H(P,D) and NOT P(D) that must be measured.>
Nothing /has/ to be measured. P's behaviour (halts, doesn't halt) when given D as input must be /established/.
No H can possibly see the behavior of P(D)
It doesn't have to.
IF IT CAN'T SEE IT THEN IT CAN'T REPORT ON IT.
Yes, it can. There is no need to see the behaviour to establish whether it halts. All the decider has to be able to see is the code.
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unequivocally specifies that the INPUT DOES NOT HALT
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