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On 5/5/2025 1:37 PM, olcott wrote:Every theorem that can be proven with an indirect proof can also be provenOn 5/5/2025 11:13 AM, Mr Flibble wrote:In other words, you're demonstrating that you don't understand proof by contradiction, a concept taught to and understood by high school students more than 50 years your junior.On Mon, 05 May 2025 11:58:50 -0400, dbush wrote:The above example is category error because it asks
On 5/5/2025 11:51 AM, olcott wrote:The category (type) error manifests in all extant halting problem proofsOn 5/5/2025 10:17 AM, Mr Flibble wrote:Which start with the assumption that the following mapping is computableWhat constitutes halting problem pathological input:I prefer to look at it as a counter-example that refutes all of the
Input that would cause infinite recursion when using a decider of the
simulating kind.
Such input forms a category error which results in the halting problem
being ill-formed as currently defined.
/Flibble
halting problem proofs.
and that (in this case) HHH computes it:
Given any algorithm (i.e. a fixed immutable sequence of instructions) X
described as <X> with input Y:
A solution to the halting problem is an algorithm H that computes the
following mapping:
(<X>,Y) maps to 1 if and only if X(Y) halts when executed directly
(<X>,Y) maps to 0 if and only if X(Y) does not halt when executed
directly
int DD()Which is a contradiction. Therefore the assumption that the above
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
https://github.com/plolcott/x86utm
The x86utm operating system includes fully operational HHH and DD.
https://github.com/plolcott/x86utm/blob/master/Halt7.c
When HHH computes the mapping from *its input* to the behavior of DD
emulated by HHH this includes HHH emulating itself emulating DD. This
matches the infinite recursion behavior pattern.
Thus the Halting Problem's "impossible" input is correctly determined
to be non-halting.
mapping is computable is proven false, as Linz and others have proved
and as you have *explicitly* agreed is correct.
including Linz. It is impossible to prove something which is ill-formed
in the first place.
/Flibble
HHH(DD) to report on the direct execution of DD() and
the input to HHH specifies a different sequence of steps.
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