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On 5/16/25 6:39 PM, olcott wrote:*Click here to get the whole article*On 5/16/2025 5:03 PM, Richard Damon wrote:Nope, since D must stay D, and D must be a fully encoded program and thus doesn't change when you make the hypothetical H.On 5/16/25 4:29 PM, olcott wrote:>On 5/16/2025 3:06 PM, Fred. Zwarts wrote:>Op 16.mei.2025 om 07:29 schreef olcott:>*Not at all. I am following these exact words*>
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its
input D until H correctly determines that its simulated D
would never stop running unless aborted then
>
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
On 5/14/2025 7:36 PM, Mike Terry wrote:
Shows exactly how to implement those words to implement
a correct Simulating Termination Analyzer. Mike provides
a complete example of how this works.
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>
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Sipser agreed to a vacuous statement, because the condition 'correctly simulates' was not met.
And by this you mean that when the spec requires
a partial simulation
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*until H correctly determines that its simulated D*
*would never stop running unless aborted*
>
You "interpret" this to mean that it must
infinitely simulate non-terminating inputs.
Which means, as I explained else, if H, after doing a partial simulation, can determine that a COMPLETE simulation of this exact input would be non-halting, it can abort.
>
Not quite. One key detail is missing.
*H correctly determines that its simulated D*
*would never stop running unless aborted*
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Is referring to what the behavior of D would be
(in the hypothetical case) where this very same
H never aborted.
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