Re: 197 page execution trace of DDD correctly simulated by HHH

On 7/1/2024 9:25 AM, Fred. Zwarts wrote:

Op 01.jul.2024 om 14:59 schreef olcott:

On 7/1/2024 3:23 AM, Fred. Zwarts wrote:

Op 30.jun.2024 om 19:20 schreef olcott:

>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>

>
It cannot possibly return, because HHH aborts itself one cycle too early, showing that the emulation is incorrect. If that is over your head, try to learn how x86 instructions work.

>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>
DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.
>
>

>
... aborted one cycle too soon. One cycle later HHH would return and DDD would return.

 What you say is counter-factual.