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On 5/26/2025 12:25 PM, Richard Heathfield wrote:It can't. Mr Olcott said so. (See above.) You /do/ believe him, right?On 26/05/2025 17:24, olcott wrote:HHH(DDD) does correctly report on the behavior that itsOn 5/26/2025 11:10 AM, Richard Heathfield wrote:>On 26/05/2025 16:42, olcott wrote:>no>
C function can see its own caller.
So because DDD calls HHH, HHH can't analyse the halting behaviour of DDD.
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Got it.
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I didn't say that.
Yes, you did.
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On 24/5/2025 in Message-ID <100sr6o$ppn2$3@dont-email.me> you said:
>You are a damned liar when you say that I said>
that HHH must report on the behavior of its caller.
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No HHH can report on the behavior of its caller
for the same reason that no function can report
on the value of the square-root of a dead cat.
Your words.
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Since DDD is HHH's caller, according to you HHH can't report on DDD's behaviour.
input specifies.
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