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On 5/31/2025 11:47 AM, dbush wrote:Nope, if that was true you would have previously identified the divergence but failed to do so.On 5/31/2025 12:37 PM, olcott wrote:No stupid. HHH performs one whole recursiveOn 5/31/2025 10:45 AM, dbush wrote:>On 5/31/2025 11:43 AM, olcott wrote:>On 5/31/2025 5:12 AM, Richard Heathfield wrote:>On 31/05/2025 10:46, Mikko wrote:>On 2025-05-30 18:40:01 +0000, olcott said:>
<snip>
>>>>
to HHH(DDD)
does specify a non-halting sequence of configurations.
No, it is not. Nobody has seen the input to HHH(DDD) running forever.
So the "non-halting" is not a verified fact.
>
The unfailingly patient Mike Terry will forgive me if I have remembered him incorrectly, but I seem to recall... wait... I can quote him:
>
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Just as a reminder I'll repeat the final outcome of all this:
>
- PO's H does decide NEVER_HALTS for TM H^ running with input <H^>.
- PO's H^ running with input <H^> in fact halts, in line with Linz logic (b) above.
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
>
...so it halts. End of, one would think.
>
>
That is the same thing as saying that you never have
to eat because you know that after you eat you will
no longer be hungry.
>
The behavior of DDD emulated by HHH before it has
been aborted is different than the behavior of DDD
emulated by HHH1 after HHH has already aborted its DDD.
>
These differences have always been there for three years
and everyone here thinks that they can just assume them away.
>
>
>
The emulation performed by HHH and HHH1 are exactly the same up to the point that HHH aborts, as you have admitted on the record:
>
*You are a damned liar*
HHH performs two recursive emulations of DDD.
HHH performs one non-recursive emulation of DDD.
>
>
Not up to the point that HHH aborts it doesn't.
>
emulation of DDD more than HHH1 ever does
On 5/6/2025 5:17 PM, dbush wrote:
> On 5/6/2025 5:03 PM, olcott wrote:
>> On 5/6/2025 3:51 PM, dbush wrote:
>>> On 5/6/2025 4:46 PM, olcott wrote:
>>>> On 5/6/2025 3:31 PM, dbush wrote:
>>>>> Then what is the first instruction emulated by HHH that differs
>>>>> from the emulation performed by UTM?
>>>>>
>>>>
>>>> HHH1 is exactly the same as HHH except that DD
>>>> does not call HHH1. This IS the UTM emulator.
>>>> It does not abort.
>>>
>>> Last chance:
>>>
>>> What is the first instruction emulated by HHH that differs from the
>>> emulation performed by HHH1?
>>
>> Go back and read the part you ignored moron.
>
> Let the record show that Peter Olcott has neglected to identify an
> instruction that HHH emulates differently from HHH1.
>
>>> Failure to provide this in your next message or within one hour of
>>> your next post in this newsgroup will be taken as your official on-
>>> the-record admission that the emulations performed by HHH and HHH1
>>> are in fact exactly the same up until the point that HHH aborts, at
>>> which point HHH did not correctly simulate the last instruction it
>>> simulated as you are previously on record as admitting.
>
> Therefore, as per the above requirements:
>
> LET THE RECORD SHOW
>
> That Peter Olcott
>
> Has *officially* admitted
>
> That the emulations performed by HHH and HHH1 are in fact exactly the
> same up until the point that HHH aborts, at which point HHH did not
> correctly simulate the last instruction it simulated as he is previously
> on record as admitting.
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