Re: DDD emulated by HHH diverges from DDD emulated by HHH1

On 6/3/25 3:57 PM, olcott wrote:

On 6/3/2025 2:37 AM, Mikko wrote:

On 2025-06-02 15:52:53 +0000, olcott said:
>

DDD correctly emulated by HHH diverges from DDD
correctly emulated by HHH1 as soon as HHH begins
emulating itself emulating DDD, marked below.

>
The DDD emulated (correctly or otherwise) by HHH is the same DDD as
the one emulated (correctly or otherwise) so both specify the same
behaviour.

 No they do not. When DDD calls its own emulator its behavior
is different than when DDD calls another different emulator.

HOW?

 The moment that HHH begins emulating itself emulating
DDD is where the emulation by HHH and HHH1 diverge.

And what x86 instruction differed in its behavior?
All you have done so far about this is to duck, dodge and LIE.

 

As soon as the emulations diverge (if not even sooner)
at lest one of the emulators is no longer emulating correctly.
>