Re: DDD emulated by HHH diverges from DDD emulated by HHH1

On 6/4/2025 9:39 PM, olcott wrote:

On 6/4/2025 8:28 PM, dbush wrote:

On 6/4/2025 9:08 PM, olcott wrote:

On 6/4/2025 7:41 PM, dbush wrote:

On 6/4/2025 8:32 PM, olcott wrote:

>
Show me this side-by-side trace and I will point out your mistake.

>
See below, which shows that the simulations performed by HHH and HHH1 are identical up to the point that HHH aborts, as you have agreed on the record.
>

 

>
False.  The correct trace is the one I posted, which shows all levels of emulation performed by HHH and HHH1.  See the corrections I made to your comments

 It is not supposed to do that.]

Yet that is exactly what it does

 It is supposed to show
the emulation of DDD by HHH1 and
the emulation of DDD by HHH
side-by-side to show the point where these
emulations diverge.

Which they don't as you explicitly agreed:
On 6/4/2025 12:38 PM, olcott wrote:
 > On 6/4/2025 4:20 AM, Fred. Zwarts wrote:
 >>
 >> That did not answer the question: WHAT INSTRUCTION, correctly simulated did that?
 >
 > When HHH1(DDD) simulates DDD it never simulates itself.
 > When HHH(DDD) simulates DDD then simulates itself simulating
 > DDD the first instruction that this simulated HHH simulates
 > diverges from the simulation that HHH1 did.
 >
 >> You cannot point to any instruction interpreted differently by the two simulators.
 >
 > There are no instructions interpreted differently.

 DDD emulated by HHH1              DDD emulated by HHH
[00002183] push ebp               [00002183] push ebp
[00002184] mov ebp,esp            [00002184] mov ebp,esp
[00002186] push 00002183 ; DDD    [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH    [0000218b] call 000015c3 ; HHH
 

DDD emulated by HHH1 emulating HHH  DDD emulated by HHH emulating HHH
[00002183] push ebp      ;          [00002183] push ebp      ;
[00002184] mov ebp,esp   ;          [00002184] mov ebp,esp   ;
[00002186] push 00002183 ; DDD      [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH      [0000218b] call 000015c3 ; HHH
                                     ### HHH aborts ###
See, the same instructions up to the point that HHH aborts
DDD emulated by HHH1 emulating HHH emulating HHH
[00002183] push ebp      ;
[00002184] mov ebp,esp   ;
[00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH
### first emulated HHH aborts ###
DDD emulated by HHH1 (continued)
[00002190] 83c404     add esp,+04
[00002193] 5d         pop ebp
[00002194] c3         ret
And the top level HHH1 emulates more instructions of DDD than the top level HHH, as those are the only ones that matter