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On 6/4/25 10:06 PM, olcott wrote:The above is not an emulation done by HHH1On 6/4/2025 8:48 PM, dbush wrote:Right, becuase HHH gives up when HHH1 proves that the complete emulation would halt.On 6/4/2025 9:39 PM, olcott wrote:>On 6/4/2025 8:28 PM, dbush wrote:>>
DDD emulated by HHH1 emulating HHH DDD emulated by HHH emulating HHH
[00002183] push ebp ; [00002183] push ebp ;
[00002184] mov ebp,esp ; [00002184] mov ebp,esp ;
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
### HHH aborts ###
>
*That is dishonest*
HHH1 emulates DDD once and this matches
the first time that HHH emulates DDD.
>
DDD emulated by HHH1 DDD emulated by HHH
[00002183] push ebp [00002183] push ebp
[00002184] mov ebp,esp [00002184] mov ebp,esp
[00002186] push 00002183 ; DDD [00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH [0000218b] call 000015c3 ; HHH
>
*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
*THE MATCHING IS NOW USED UP*
>Which is the emulation done by HHH1, that shows that HHH will abort and return 0 and thus DDD halts.
*Then DDD emulated by HHH diverges from DDD emulated by HHH1*
>
DDD emulated by HHH emulating itself
[00002183] push ebp ;
[00002184] mov ebp,esp ;
[00002186] push 00002183 ; DDD
[0000218b] call 000015c3 ; HHH
>
>
Which goes against the INCORRECT assumptions that HHH used, and thus HHH was just incorrect, and you are proven to not understand how logic works,--
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