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On 6/8/2025 10:54 PM, Keith Thompson wrote:Nobody denied it. You are fighting windmills.olcott <polcott333@gmail.com> writes:Great. No one else besides you and I agree that DDDOn 6/8/2025 10:31 PM, Keith Thompson wrote:>olcott <polcott333@gmail.com> writes:>void DDD()Do not imply that I support your claims.
{
HHH(DDD);
return;
}
>
The *input* to simulating termination analyzer HHH(DDD)
specifies recursive simulation that can never reach its
*simulated "return" instruction final halt state*
>
*Every rebuttal to this changes the words*
I am not implying anything. I am directly stating
that you have agreed that when DDD is correctly simulated
by HHH that it cannot possibly reach its own simulated
"return" instruction and terminate normally.
Endless recursion is endless recursion. Correctly simulated endless
recursion is endless recursion.
correctly simulated by HHH cannot possibly reach its
*simulated "return" instruction final halt state*
Indeed, it shows that simulation is not the right way to try to refute the proof of the halting theorem, because a simulator will never be able to simulate itself correctly up to the end.This has no useful or interestingIt is very useful because it is isomorphic to this:
consequences. Do you agree?
>
(The standard Halting Problem counter-example input)
int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}
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