Re: The execution trace of HHH1(DDD) shows the divergence

On 6/18/25 11:36 AM, olcott wrote:

On 6/18/2025 4:33 AM, Mikko wrote:

On 2025-06-07 14:32:36 +0000, olcott said:
>

The execution trace of HHH1(DDD) shows the divergence
of DDD emulated by HHH from DDD emulated by HHH1.

>
The divergence means that at least one of them simulates
incorrectly. Next should be determined which one.
>

 *One might incorrectly guess that*
When one tries to find even a single 100% specific
instruction that is simulated incorrectly, one fails.

Except for the LAST one it does.
SInce the DEFINITION of each instruction (besides halt) includes: and then execute the next instuction in sequence. (as part of the general operaiton of the machine)

 When one does not understand these things well
enough to begin looking for a single instruction
that is simulated incorrectly, then one is dishonest
when they claim that the simulation is incorrect.
 

Right, since you think x86 computers can validily just stop running at any point in time, you seem to not understand what you are talking about.