Re: How do simulating termination analyzers work?

On 6/24/2025 3:57 AM, Mikko wrote:

On 2025-06-23 16:53:59 +0000, olcott said:
 

On 6/23/2025 2:15 AM, Mikko wrote:

On 2025-06-22 19:23:37 +0000, olcott said:
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On 6/22/2025 4:02 AM, Mikko wrote:

On 2025-06-21 17:35:58 +0000, olcott said:
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On 6/21/2025 4:54 AM, Mikko wrote:

On 2025-06-20 17:17:40 +0000, olcott said:
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On 6/20/2025 3:51 AM, Mikko wrote:

On 2025-06-19 07:02:27 +0000, olcott said:
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On 6/19/2025 1:39 AM, Mikko wrote:

On 2025-06-18 18:28:43 +0000, Mr Flibble said:
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On Wed, 18 Jun 2025 08:53:07 -0500, olcott wrote:
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On 6/18/2025 6:01 AM, Richard Damon wrote:

On 6/17/25 9:54 PM, olcott wrote:

On 6/17/2025 8:19 PM, Richard Damon wrote:

On 6/17/25 4:34 PM, olcott wrote:

void Infinite_Recursion()
{
   Infinite_Recursion();
   return;
}
>
void Infinite_Loop()
{
   HERE: goto HERE; return;
}
>
void DDD()
{
   HHH(DDD);
   return;
}
>
When it is understood that HHH does simulate itself simulating DDD
then any first year CS student knows that when each of the above are
correctly simulated by HHH that none of them ever stop running
unless aborted.

>
WHich means that the code for HHH is part of the input, and thus
there is just ONE HHH in existance at this time.
>
Since that code aborts its simulation to return the answer that you
claim, you are just lying that it did a correct simulation (which in
this context means complete)
>
>

*none of them ever stop running unless aborted* *none of them ever
stop running unless aborted* *none of them ever stop running unless
aborted*
>
Do you agree or can you refute THIS EXACT POINT?
Do you agree or can you refute THIS EXACT POINT?
Do you agree or can you refute THIS EXACT POINT?
>
>
>

How about the fact that if they abort, they never did a correct
simulation,

>
*You are not addressing THE EXACT POINT*
>
*When HHH never aborts any of the above functions then*
(a) None of the functions ever stops running.
(b) Each of the above functions stops running anyway.

>
You need to be clear that you are not making a claim about general
undecidability but a claim about the SPECIFIC CASE of pathological self
reference present in the classic Halting Problem definition .. the trolls
here (especially Damon and Mikko) like to ignore that you are doing that.

>
He is not doing even that. What he is doing is totally outside of the
scope of the halting problem. He has already verified that DDD halts
and that HHH does not report that DDD halts. Nothing else is relevant
in context of the halting problem.
>
If his intent is to deceive he should avoid clarity at least as much
as he has recently done. His switch from "halting decider" to
"termination analyzer"

>
is a more accurate term for what I am referring to.

>
Not really as you are only talking about programs that do not take
any input. Termination analysis is about programs that do take input.

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Inputs are typical yet not required.

>
Ability to analyze (at least some) programs that take inputs is
required.

>
No that is wrong.

>
Can you quote any author allowing a termination analyzer that is restricted
to programs that do not take any input?

>
The ability to correctly determine the halt status
of at least one program that takes no inputs meets
the requirement of being a termination analyzer for
that one program.

>
It does not prove that all requirements are met, in particular the
requirement that the analyzer must be able to analyze programs that
do take input.

>
That is a bogus requirement.

 No, it is not. It is essential to the meaning of the term.
A nut cracker is not a hammer although both can produce the same
effenct on nuts.
 

A termination analyzer determines the halt status
of a program for every input that this program takes.
When it does this for a program that takes no inputs
it is still doing this for every input that this
program takes.
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer