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On 6/25/2025 2:38 AM, Mikko wrote:The input in HHH(DDD) is the same DDD that is executed in DDD()On 2025-06-24 14:39:52 +0000, olcott said:*HHH(DDD) the input to HHH specifies non-terminating behavior*
*ChatGPT and I agree that*No matter who agrees, the directly executed DDD is mote than
The directly executed DDD() is merely the first step of
otherwise infinitely recursive emulation that is terminated
at its second step.
merely the first step of otherwise infinitely recursive
emulation that is terminated at its second step. Not much
more but anyway. After the return of HHH(DDD) there is the
return from DDD which is the last thing DDD does before its
termination.
The fact that DDD() itself halts does not contradict that
because the directly executing DDD() cannot possibly be an
input to HHH in the Turing machine model of computation,
thus is outside of the domain of HHH.
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