Liste des Groupes | Revenir à theory |
Op 25.jun.2025 om 17:42 schreef olcott:*No, you are using an incorrect measure*On 6/25/2025 2:38 AM, Mikko wrote:Why repeating claims that have been proven incorrect.On 2025-06-24 14:39:52 +0000, olcott said:>
>*ChatGPT and I agree that*>
The directly executed DDD() is merely the first step of
otherwise infinitely recursive emulation that is terminated
at its second step.
No matter who agrees, the directly executed DDD is mote than
merely the first step of otherwise infinitely recursive
emulation that is terminated at its second step. Not much
more but anyway. After the return of HHH(DDD) there is the
return from DDD which is the last thing DDD does before its
termination.
>
*HHH(DDD) the input to HHH specifies non-terminating behavior*
The fact that DDD() itself halts does not contradict that
because the directly executing DDD() cannot possibly be an
input to HHH in the Turing machine model of computation,
thus is outside of the domain of HHH.
>
The input to HHH is a pointer to code, that includes the code of HHH, including the code to abort and halt. Therefore, it specifies a halting program.
That HHH is programmed to be blind for that behaviour does not change the specification.--
Les messages affichés proviennent d'usenet.