Re: Who here is too stupid to know that DDD correctly simulated by HHH cannot possibly reach its own return instruction?

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Sujet : Re: Who here is too stupid to know that DDD correctly simulated by HHH cannot possibly reach its own return instruction?
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theory
Date : 03. Aug 2024, 15:04:11
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v8ldcs$3fcgg$2@dont-email.me>
References : 1 2 3
User-Agent : Mozilla Thunderbird
Op 03.aug.2024 om 15:50 schreef olcott:
On 8/3/2024 3:14 AM, Fred. Zwarts wrote:
Op 02.aug.2024 om 22:57 schreef olcott:
Who here is too stupid to know that DDD correctly simulated
by HHH cannot possibly reach its own return instruction?
>
void DDD()
{
   HHH(DDD);
   return;
}
>
>
Which proves that the simulation is incorrect.
 When are you going to understand that you are not allowed
to disagree with the semantics of the x86 language?
 
I do not disagree.
When are you going to understand that it is a deviation of the semantics of the x86 language to skip instructions of a halting program, only because you are dreaming of a non-halting HHH?
DDD is a misleading and unneeded complication. It is easy to eliminate DDD:
        int main() {
          return HHH(main);
        }
This has the same problem. This proves that the problem is not in DDD, but in HHH, which halts when it aborts the simulation, but it decides that the simulation of itself does not halt.
It shows that HHH cannot possibly simulate itself correctly.

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