Re: Who knows that DDD correctly simulated by HHH cannot possibly reach its own return instruction final state?

On 8/4/2024 1:22 AM, Fred. Zwarts wrote:

Op 03.aug.2024 om 18:35 schreef olcott:

 >>>> ∞ instructions of DDD correctly emulated by HHH[∞] never

reach their own "return" instruction final state.
>
So you are saying that the infinite one does?
>

 Dreaming again of HHH that does not abort? Dreams are no substitute for facts.
The HHH that aborts and halts, halts. A tautology.

void DDD()
{
   HHH(DDD);
   return;
}
That is the right answer to the wrong question.
I am asking whether or not DDD emulated by HHH
reaches its "return" instruction.

The correct simulation of a halting program halts. A truism.
HHH cannot possibly simulate itself correctly.
 

So by correctly you must mean that HHH incorrectly
skips the call from DDD to HHH(DDD).

I am happy that you were not a member of our team when we developed simulators to check the design of big detector systems.

Crash dummy simulators?
Not x86 emulators.

We knew that a simulation is only correct if it matches the reality. But you seem to think that it is correct that a simulator does not match the reality.

The reality is that DDD does call HHH(DDD) in recursive
simulation. When you ignore this then you are out-of-touch
with reality.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer