Sujet : Re: Who knows that DDD correctly simulated by HHH cannot possibly reach its own return instruction final state?
De : abc (at) *nospam* def.com (olcott)
Groupes : comp.theoryDate : 04. Aug 2024, 19:59:03
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v8oj1n$6kik$3@dont-email.me>
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User-Agent : Mozilla Thunderbird
On 8/4/2024 1:51 PM, Richard Damon wrote:
On 8/4/24 9:53 AM, olcott wrote:
On 8/4/2024 1:22 AM, Fred. Zwarts wrote:
Op 03.aug.2024 om 18:35 schreef olcott:
>>>> ∞ instructions of DDD correctly emulated by HHH[∞] never
reach their own "return" instruction final state.
>
So you are saying that the infinite one does?
>
>
Dreaming again of HHH that does not abort? Dreams are no substitute for facts.
The HHH that aborts and halts, halts. A tautology.
>
void DDD()
{
HHH(DDD);
return;
}
>
That is the right answer to the wrong question.
I am asking whether or not DDD emulated by HHH
reaches its "return" instruction.
But the "DDD emulated by HHH" is the program DDD above,
When I say DDD emulated by HHH I mean at any level of
emulation and not and direct execution.
DDD emulated by HHH a googleplex levels deep is included
in DDD emulated by HHH.
Yo keep screwing around trying to twist the meaning of the
actual words that I say.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
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