Sujet : Re: Replacement of Cardinality
De : noreply (at) *nospam* example.org (joes)
Groupes : sci.mathDate : 16. Aug 2024, 17:50:39
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <2e01bd19df4cd4dadc417349d86040fa204b960b@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Fri, 16 Aug 2024 16:19:17 +0000 schrieb WM:
Le 15/08/2024 à 18:16, Jim Burns a écrit :
On 8/15/2024 9:52 AM, WM wrote:
⎜ Assume NUF(x) = 0 and x > 0
We assume that NUF(0) = 0 and many unit fractions are within (0, 1].
We can reduce the interval to (0, x) c [0, 1]. Let x converge to 0.
Then the number of unit fractions diminishes. Finally there is none
remaining. But never, for no interval (0, x), more than one unit
fraction is lost. Therefore there is only one last unit fraction.
Taking steps only until the next unit fraction, you never reach 0.
-- Am Sat, 20 Jul 2024 12:35:31 +0000 schrieb WM in sci.math:It is not guaranteed that n+1 exists for every n.
…