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WM <invalid@no.org> wrote:It gives unfamiliar results because you have no clear picture of actual infinity. If all natnumbers are there and if 2n is greater than n, then the doubled numbers do not fit into ℕ. But note, that is only true if all natnumbers do exist.Am 09.10.2024 um 18:12 schrieb Alan Mackenzie:WM <wolfgang.mueckenheim@tha.de> wrote:You've misunderstood the nature of N. The set is not
{1, 2, 3, ..., ω}, it is {1, 2, 3, ...}.I use ℕ U {ω} for clarity.You would do better not to do so. It gives wrong results.
Fine, then you can follow the above discussion. Either doubling creates new natural numbers. Then not all have been doubled. Or all have been doubled, then some products fall outside of ℕ.Numbers multiplied by 2 do not remain unchanged. That is not intuitionTrue,
but mathematics.
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