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On 21.10.2024 01:04, joes wrote:Why are the dark numbers unordered? is n + say_anything_that_is_greater_than_zero, unordered where n can be > the result?Am Sat, 19 Oct 2024 10:23:05 +0200 schrieb WM:No, also the transfinite numbers are ordered. But for dark numbers the ordering is inaccessible anyhow.That is not possible if all natural numbers are doubled. The resultThis destroys the ordering. If m>n, then 2m>2n.
covers the interval (0, ω*2) twice as large as the original one (0, ω).
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