Sujet : Re: New equation
De : chris.m.thomasson.1 (at) *nospam* gmail.com (Chris M. Thomasson)
Groupes : sci.mathDate : 26. Feb 2025, 00:00:04
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <vpli1k$27a25$1@dont-email.me>
References : 1 2 3 4
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On 2/25/2025 12:21 AM, Barry Schwarz wrote:
On Mon, 24 Feb 25 21:11:40 +0000, Richard Hachel <r.hachel@tiscali.fr>
wrote:
Le 24/02/2025 à 21:23, Barry Schwarz a écrit :
On Mon, 24 Feb 25 18:52:17 +0000, Richard Hachel <r.hachel@tiscali.fr>
>
A quartic always has four roots.
>
Here, I would still put a small caveat.
The fact of saying that an equation of degree n has n roots is perhaps not
entirely correct.
I ask myself the question.
If for example we write f(x)=x^3+3x-4, it is indeed an equation of degree
3.
But how many roots, and what are they?
I asked this question to mathematicians, and to artificial intelligence,
and I was given three roots, but they are incorrect, because those who
answer do not seem to understand the real concept of imaginary numbers.
There is in fact only one root.
A very strange root composed of a real root and a complex root. Both
placed on the same point A(1,0) and A(-i,0).
>
R.H.
A cubic has three roots.
The roots of your equation are 1, (-1+i*sqrt(15))/2, and
(-1-i*sqrt(15))/2.
I have no idea what you mean by a point A(-i,0).
Nor do I. Humm...