Sujet : Re: [SR] Usefulness of real velocities in accelerated relativistic frames of reference.
De : r.hachel (at) *nospam* tiscali.fr (Richard Hachel)
Groupes : sci.physics.relativityDate : 14. Mar 2024, 17:18:32
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Le 14/03/2024 à 15:02, "Paul B. Andersen" a écrit :
Den 14.03.2024 03:09, skrev Richard Hachel:
Contradicting fact:
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So this is wrong.
You can see the correct derivation here:
https://paulba.no/pdf/TwinsByMetric.pdf
See chapter 2.3, equation (15)
Vr(t) = a⋅t/√(1+(a⋅t/c)²)
Note that:
Vr → a⋅t when t → 0
Vr → c when t → ∞
Your problem is that you do not understand the difference
between proper acceleration of the rocket, and the rocket's
coordinate acceleration in the inertial frame.
If A is the coordinate acceleration in K, we have:
A = dVr/dt = a/(√(1+(a⋅t/c)²))³
Note that:
A → a when t → 0
A → 0 when t → ∞
So Vr(t) = ∫(from 0 to t)A⋅dt = a⋅t/√(1+(a⋅t/c)²)
You claim:
According to SR is the average speed of the rocket Vm(t) = Vr(t)/2
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Contradicting fact:
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This is wrong.
Vr(t) = a⋅t/√(1+(a⋅t/c)²)
The average speed Vm at the time t is:
Vm = (integral from t=0 to t=t of Vr(t)dt)/t
Vm = c²⋅(√(1+(a⋅t/c)²)-1)/a⋅t
Note that:
Vm → a⋅t/2 when t → 0
Vm → c when t → ∞
So:
Vm/Vr → 1/2 when t → 0
rm/Vr → 1 when t → ∞
So for any t > 0 Vm > Vr/2
It is not possible to make SR predict anything else!
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You don't understand anything I'm telling you...
In these conditions, it is very difficult to discuss.
R.H.