Re: Space-time interval (2)

Den 13.08.2024 14:46, skrev Richard Hachel:

Le 13/08/2024 à 12:44, "Paul.B.Andersen" a écrit :

>
https://paulba.no/pdf/TwinsByMetric.pdf
Chapter 1.

 There are equations that are correct in your pdf, but also equations that are incorrect.

I think you know that all are correct according to SR.

Unfortunately, I don't have time to do a thorough search, and to circle in red everything that is wrong and tell you why.
Anyway, it would be useless, and I no longer have the courage (I'm old, you know now) to want at all costs to give water to donkeys that are not thirsty.

You are right, I am not interested in why you claim SR is wrong,
but you keep carrying water to the donkey anyway.

I post here for fun, but I don't want to exhaust myself gesticulating in the void anymore.

So you have given up gesticulating about universal anisochrony
and why that makes it impossible to have synchronous clocks
in Oslo and Paris?
Try to explain it again?
|> Den 22.07.2024 21:37, skrev Paul.B.Andersen:
|>>
|>> You know of course that all clocks in the same time zone
|>> are synchronous. In France and Norway clocks are currently
|>> showing UTC + 2 hour, so my clock and your clock are actually
|>> synchronous.
|>>
|>> Please explain why our clocks are NOT synchronous.
|>> (To within few seconds|
|
|> Den 22.07.2024 23:55, Richard Hachel responded:>
|>> But I keep explaining it to you.
|>>
|>> This is a property of space that can be called universal anisochrony.
|>>
|>> This does not translate into the idea that the “plan of present time”
|>> so dear to physicists does not exist, it is a thought that seems
|>> logical to them, but it is an abstract thought.
|>>
Let's assume that both clocks show UTC + 2h within a second.
I leave Oslo Airport (Gardemoen Airport) when the watch on
the airport shows 12.00.00 ± 1 s
I arrive at Paris Airport (Charles De Gaulle Airport) when
the watch on the airport shows 13.30.32 ± 1 s.
The difference is T = 1h 30m 32 ± 2 s
The distance in the ground frame between the airports is
L = 1358.03 ± 0.1 km
v = T/L = 250.01 ± 0.11 m/s = 900.0 ± 0.4 km/h
Please explain why this is not a real speed
in the ground frame.
Richard, will you flee yet again? :-D
--
Paul
https://paulba.no/