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>"Observable"?
"If two different observers travel an identical path in equal observable times,
then their proper times will necessarily be equal.This is not possible.
Let's set up a Galilean frame of reference, in which a Galilean mobile moves from left to right on the x axis.This is assuming a constant velocity of v = 0.9291c, yes. The proper time
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When it goes to O, in R, we click.
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When it passes x, let's say 12 al, we click.
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For example, we obtain To=12.915.
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Or a speed of Vo=x/To=0.9291c
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Tr=To.sqrt(1-Vo²/c²)=4.776
Let us pose another body, but this time in uniformly accelerated motion,WHO sees the "uniformly accelerated motion"? The earth observer or the one
and whose speed will be specially chosen so that To=12.915.Neither the earth observer nor the ship observer sees a "specially chosen"
This means that in R, if they leave together, they arrive together (even if they do not have the same speed between them).The equations are here (Equ. 6a):
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