Sujet : Re: Hypothetical possibilities
De : richard (at) *nospam* damon-family.org (Richard Damon)
Groupes : comp.theory comp.ai.philosophyDate : 20. Jul 2024, 21:10:16
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <e58a2ea9135650d687ad29b66149a0a7c78108e0@i2pn2.org>
References : 1 2 3 4 5
User-Agent : Mozilla Thunderbird
On 7/20/24 4:02 PM, olcott wrote:
On 7/20/2024 2:36 PM, Fred. Zwarts wrote:
Op 20.jul.2024 om 21:09 schreef olcott:
On 7/20/2024 2:00 PM, Fred. Zwarts wrote:
Op 20.jul.2024 om 17:28 schreef olcott:
void DDD()
{
HHH(DDD);
}
>
int main()
{
DDD();
}
>
(a) Termination Analyzers / Partial Halt Deciders must halt
this is a design requirement.
>
(b) Every simulating termination analyzer HHH either
aborts the simulation of its input or not.
>
(c) Within the hypothetical case where HHH does not abort
the simulation of its input {HHH, emulated DDD and executed DDD}
never stop running.
>
This violates the design requirement of (a) therefore HHH must
abort the simulation of its input.
>
And when it aborts, the simulation is incorrect. When HHH aborts and halts, it is not needed to abort its simulation, because it will halt of its own.
>
So you are trying to get away with saying that no HHH
ever needs to abort the simulation of its input and HHH
will stop running?
>
>
No, you try to get away with saying that a HHH that is coded to abort and halt, will never stop running, only because you are dreaming of *another* HHH that does not abort.
>
*You know that I didn't say anything like that*
Unless I refer to the infinite set of every possible
HHH my reviewers try to get away with saying that I am
referring to the wrong HHH.
void DDD()
{
HHH(DDD);
return;
}
DDD correctly simulated by pure function HHH cannot
possibly reach its own return instruction.
And the problem you ignore is that each HHH is given the DDD that calls itself, and not some other HHH, and thus you can't look at the other HHHs behavior with their different behavior (in particular, the HHH/DDD pair where HHH doesn't abort) but look at giving this exact input, calling this exact HHH to a "correct emulator" that doesn't abort its emulation.
You logic of looking at other HHHs is just a LIE and proves you don't understand either Computations or Logic, or even what Truth itself is.
EVERY DDD that calls an HHH that aborts and returns will reach its own return instruction. so your claim is just a lie.
You confuse that DDD with the PARTIAL emulation that HHH did, which doesn't show the full behavior of DDD, only partial.
This appears to be because you just don't understand the difference between Truth and Knowledge which shows you don't really know what EITHER of them actually is, so, you are just proving you total inability tto understand how logic actually works.