Re: Any honest person that knows the x86 language can see...

Liste des GroupesRevenir à ca philosophy 
Sujet : Re: Any honest person that knows the x86 language can see...
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory comp.ai.philosophy
Date : 29. Jul 2024, 20:35:16
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v88qtk$k3pj$1@dont-email.me>
References : 1 2
User-Agent : Mozilla Thunderbird
On 7/29/2024 2:18 PM, Fred. Zwarts wrote:
Op 29.jul.2024 om 16:07 schreef olcott:
HHH(Infinite_Recursion) and HHH(DDD) show the same non-halting
behavior pattern in their derived execution traces of their
inputs.
>
Correct emulation is defined as emulating the machine language
input according to the x86 semantics specified by this input.
>
For DDD correctly emulated by HHH this includes HHH emulating
itself emulating DDD according to the x86 semantics of itself.
>
HHH(DDD) shows the exact same execution trace behavior pattern
as HHH(Infinite_Recursion) where 3-4 instructions are repeated
with no conditional branch instructions in this trace that could
prevent them from endlessly repeating.
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}
 No, the HHH that aborts after N cycles has a similar behaviour as
 
So you don't even know that infinite recursion is non-halting behavior.
You can go back and try again on this same post I am not looking at
anything else that you say.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

Date Sujet#  Auteur
29 Jul 24 * Any honest person that knows the x86 language can see...7olcott
29 Jul 24 +* Re: Any honest person that knows the x86 language can see...5Fred. Zwarts
29 Jul 24 i`* Re: Any honest person that knows the x86 language can see...4olcott
29 Jul 24 i `* Re: Any honest person that knows the x86 language can see...3Fred. Zwarts
29 Jul 24 i  `* Re: Any honest person that knows the x86 language can see...2olcott
30 Jul 24 i   `- Re: Any honest person that knows the x86 language can see...1Fred. Zwarts
30 Jul 24 `- Re: Any honest person that knows the x86 language can see... DDD will HALT if HHH answers1Richard Damon

Haut de la page

Les messages affichés proviennent d'usenet.

NewsPortal